In the original post I didn't put in any numbers for the calculation for the ovoid, but I'm getting bolder. Also rumor for a buyout circulating.

Using cut-out pictures from the website to a scale of 1.5 inches equals 300 meters, a putty model was constructed of the red mass and the ovoid. After this was disassembled, the plastic was rolled into a blue cylinder, and a red cylinder.

Note this is very crude.

Silly putty was fashioned into a model made from printed copies from the website that were enlarged then cut out. The pink anomaly copy was 1 ½” deep, equaling 300 m. After completion, (using two dimensional forms), pictures were taken and the blue and the red models were rolled into two cylinders. The ovoid cylinder was 2.5 inches in height by 2 inches in diameter. The red mass was 1.5/8 inches in height and 2 inches in diameter.

Surprisingly my red (higher conductivity) volume makes up about 65% of the ovoid.

Volume of the red cylinder is radius2 (1/2 of 600 m diameter) or 3002 (radius2) x pi x 487m (height) is 1. 5/8 =300m +187m) using cylinder volume formula) =137 million cu meters

Volume of the blue cylinder is 300m radius x 900m height (each inch represents 300m) using formula pi x r2 etc gives 254 million cubic meters

Subtract the red from the blue to give the volume of the lower grade conducting rock =116 million m3 (blue) and 137million tons (red) of the higher grade. (The 116 is the pink shell around the red)

To give the weight in tons, I will multiply x2. Crushed rock weight can vary from 1.6-2.5 x per cubic meter of rock apparently, depending on the amount of air between the rock particles.

The red volume 137.8 x2 gives 275 million tons

The blue volume is 116 x2 = 232 million tons

The lower grade @1 gm/t is 232 million g, (divide by 31) or 7.4 million troy ounces. A very, very low estimate.

@2 " " 14.8 " " "

The higher grade guessing @ 5 gms/t is 275x5 million = 1375 million gms. Divide by 31 (troy ounces) or 44 million ounces. (The higher grade may higher, similar to Dynacor)

Total estimate for the one anomaly is 51.4 million ounces, using the lower grade of 1gm/t or 58.8 million using 2gm/t for the pink part of the website illustration. My colour is blue.

From the 10-101 Paul Gray report, (p.9) Dynacor next door has confirmed inferred 1.4 million tons grading 16.4 g/t of gold adding up to almost 607,000 ounces in only 3/10 veins

Note also that the bottom horizontal representation in the website cross section view shows mostly green colourations except between the two anomalies, so that the rock outside the anomalies might contains disseminated gold all the way down, perhaps 1-2 gms per ton.

Also, the survey stopped at the edge of the old SLI boundary so the anomaly probably continues to the southwest into the new property.

When the 3D come in the calculations will all be printed out for us!