Sculpin, I know when those numbers were posted, (that I did, then Hog verified) I really wished I could take that post back, cause ya, they did seem just too much to be real, and they still do? But it was just fun math. Hog put a very good disclaimer at the end of his, which I should have as well. Oh well, live & learn.

But, if you want to compare my calculations from the other day, to these you have here today, here we go:

Your numbers said 1316 Million T @.5g/T which =21.3 Million OZ

They got that by: 1316MT X 0.5g/T X 1oz/31.1g = 21.2 Million OZ

Our formula, to get the T, we use the ovoid calculation which automatically takes approx 52% scaling factor. I also just took the 1st priority targets, with the volumes they gave in the report. In the report they also say to use 2.75T/M3, where as Hog uses 2, and I use 2.5 (so we're a little conservative there as well) It also did not include the volume from the original anomally 1450X400X450, and it also did not include the total volume from T8 anomally) But anyway, here would be my calculation with the data from above:

4/3 X 3.14 X 1/8 X 1391.5 Million M3 (targets T1-T18) X 2.5T/M3 X 0.5g/T X 1oz/31.1g

29.3 Million OZ

Would 0.5 g/T show up on the Quantec data, not sure? It still seems like a very large number, but that's just how it calculates out.

Thanks BOW2U