Great post as usual PW. So if we can take those measurement DE1 would be 40*300*200 or 2.4M meters cube, times this by sg of 3.9 and you have 9.36M tonnes of ore. For B this same work yiels 8.14 M tonnes of ore and for C this yields, 2.184 M tonnes of ore. This would give us a total of 19.684M tonnes of ore. Now, so far DE1 seems lower than the calculation here, somewhere between 5 and 7 seems to be agreed upon. so about 2 thirds of this number. So if we apply the same rational to A+B+C you end up with 13 M tonnes of ore. This would be great and probably would give us enough tonnage for a mine. Than our valuation model would go up to at least a 20% valuation which would increase our sp significantly.
Warmest regards,
Gl.